eval实现shell变量赋值给变量
j=1
for i in `seq 1 10`
do
let j=j+1
eval w$j=$i
eval echo \$w$j
done
eval首先扫描命令行进行所有的替换，然后再去执行命令。
- Next story shell判断字符串是否存在于数组中
- Previous story c header files matching you running kernel were not found
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